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8.69x^2+182.49x+290.08=0
a = 8.69; b = 182.49; c = +290.08;
Δ = b2-4ac
Δ = 182.492-4·8.69·290.08
Δ = 23219.4193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(182.49)-\sqrt{23219.4193}}{2*8.69}=\frac{-182.49-\sqrt{23219.4193}}{17.38} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(182.49)+\sqrt{23219.4193}}{2*8.69}=\frac{-182.49+\sqrt{23219.4193}}{17.38} $
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